Verifying tautologies with Haskell
join the mathspp mailing list Pt En < change language A tautology is a formula that is true regardless of the logical value we attribute to the variables it contains. For example, the propositional formula $P \vee \neg P$ is always true, regardless of $P$ being true or false. But not every tautology is as simple as the one I just showed. For example, showing that $$(P \implies Q) \implies [(Q \implies R) \implies (P \implies R)]$$ is a tautology requires a bit more thought. But thinking is too tiring, so let us write a Haskell program that takes a formula and decides if the formula is a tautology or not! (By the way, said program is available in my GitHub ...) First we need to be able to represent a proposition and we will create a data type just for that. We will call our type "Prop", from proposition, from propositional logic. where we provided data constructors for all sorts of propositional formulas. The idea is that now the formula $P \vee \n